- Oct 10, 2011
- 5
- 0
Okay, so I understand that you need 5 A's and 2 B's, and that there are certain allowable C's. But If you have, say, 3 A's and 4 B's, will they count the extra 2 B's in place of the missing 2 A's, or do you then have to add A's? Because on most of my events I don't have enough A's but I have enough B's to make up for it if this is possible.